b^4-ab^3+b^2c=

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Solution for b^4-ab^3+b^2c= equation:


Simplifying
b4 + -1ab3 + b2c = 0

Reorder the terms:
-1ab3 + b2c + b4 = 0

Solving
-1ab3 + b2c + b4 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1b2c' to each side of the equation.
-1ab3 + b2c + -1b2c + b4 = 0 + -1b2c

Combine like terms: b2c + -1b2c = 0
-1ab3 + 0 + b4 = 0 + -1b2c
-1ab3 + b4 = 0 + -1b2c
Remove the zero:
-1ab3 + b4 = -1b2c

Add '-1b4' to each side of the equation.
-1ab3 + b4 + -1b4 = -1b2c + -1b4

Combine like terms: b4 + -1b4 = 0
-1ab3 + 0 = -1b2c + -1b4
-1ab3 = -1b2c + -1b4

Divide each side by '-1b3'.
a = b-1c + b

Simplifying
a = b-1c + b

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